Heron’s Formula : CBSE Class 9 Chapter 12-TTRC-Learn Free and Paid Courses Online | Online Courses with Certificate | Live Kids Coding Classes from Experienced faculties

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Before proceeding to Heron’s formula let us recall the following formulas.

Geometric Shapes	Perimeter	Area
Triangle	$a+b+c$	$\frac { 1 }{ 2 } bh$
Rectangle	$2(l+b)$	$lb$
Square	$4s$	${ s }^{ 2 }$
Trapezium/Trapezoid	$a+b+c+d$	$h\frac { { b }_{ 1 }+{ b }_{ 2 } }{ 2 }$
Parallelogram	$2(b+h)$	$bh$
Circle	(known as circumference) $2\pi r$	$\pi { r }^{ 2 }$

Watch the above table, If we want to find the area of a triangle whose base and height is known to us then the formula is $a+b+c$ $\frac { 1 }{ 2 } bh$ . But if we want to find the area of a scalene triangle, then we can find it easily using Heron’s formula.

According to Heron’s formula, Area of a triangle = $\sqrt { s(s-a)(s-b)(s-c) }$ , where a,b,c are three sides of the triangle and s is the semi-perimeter or half-perimeter of the triangle.

Heron’s Formula can also be used to find area of a quadrilateral if sides and one diagonal are given. First divide the quadrilateral into two triangles, find their area using Heron’s formula and again add them.

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CBSE Class 9th Math

Heron’s Formula : CBSE Class 9 Chapter 12

For Video Tutorial and Textbook Solutions Click Here to download Math Tuition App from Play Store.

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CBSE Class 9th Math

For Video Tutorial and Textbook Solutions Click Here to download Math Tuition App from Play Store.

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